A sample of gas is compressed by an average pressure of 0.50 atmosphere so as to decrease its volume from 400 cm 3 to 200 cm 3 . During the process 8.00 J of heat flows out to surroundings. The change in internal energy of the system is
Text Solution
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+2.13J
Here, 
V = 200 - 400 = -200 cm 3
A we know 1 Litre = 1000 cm 3
V = -0.2 Litre.
External Pressure (P) = 0.50 then
Work done = -P 
Y = +0.50 (0.2)
= +0.1 atm Litre
and 1 litre-atmosphere = 101.3 Joule
W = +10.13 Joule
According to First law of thermodynamics
q = 
E - W
then 
E = q + W
Given q = -8.00 J
E = -8 + 10.13 = 2.13 Joule
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